The carbon carbon bond (C-C for short) is probably one of the simplest functional groups. A functional group is a group of atoms (or sometimes just one atom) that have a characteristic chemical property.
We have already seen that a C-C single bond is formed with sp3 hybridisation. The name of the group of molecules that contain only C-C single bonds and C-H bonds is the alkanes.
Alkanes can rotate freely about a single C-C bond.
One important property of carbon is that the overlap of an sp3 orbital with another carbon is not limited to one per atom, but can be 2,3 or even 4. This means that we can form carbon chains:
And these chains can be branched e.g.:
Depending on the number of carbon atoms it is attached to, a carbon is called primary (1), secondary (2), tertiary (3) or quaternary (4).
It is useful to know some of the names of these compounds:
Formula | Name |
CH4 | Methane |
C2H6 | Ethane |
C3H8 | Propane |
C4H10 | Butane |
C5H12 | Pentane |
C6H14 | Hexane |
There are also some useful abbreviations of groups of atoms (parts of a molecule – not a complete molecule) commonly encountered (the wavy line represent where the group is joined to the rest of the molecule):
Structure | Name |
Propyl | |
Isopropyl | |
Butyl | |
sec-Butyl | |
Isobutyl | |
tert-Butyl |
Properties:
Alkanes are actually very inert. Despite their tendency to burn (all the alkanes up to octane are highly flammable, and many beyond octane burn readily), which gives the impression that they are reactive, they don’t react with much else.
One of the few things they do react with is radicals. A radical is a species with an unpaired electron, and is highly reactive. They are denoted by drawing a dot (.) next to them to represent the unpaired electron. An example of a simple radical is a chlorine atom (i.e. Cl, not Cl2). The formation of Cl. from Cl2can be achieved with ultraviolet light. If this is done in the presence of an alkane, then a chain reaction occurs (there will be more detail on radical reactions, in the radical section):
etc.
As you can see, the reaction systematically substitutes one Cl atom for each H atom, so (assuming there is enough chlorine) we will end up with CCl4.